📘 Raoult’s Law

 Sure! Here's a simple and complete explanation of Raoult’s Law, perfect for Class 12 Chemistry students (CBSE/RBSE/NCERT):


📘 Raoult’s Law

(From NCERT Class 12 Chemistry – Chapter 1: Solutions)


💡 What is Raoult’s Law?

Raoult’s Law gives a relationship between the vapour pressure of a component in a solution and its mole fraction in the liquid phase.

📌 Statement of Raoult’s Law:
The partial vapour pressure of each volatile component in a liquid solution is directly proportional to its mole fraction in the solution.


🔬 Mathematical Expression:

For a binary solution of two volatile liquids, component 1 and 2:

  • Partial pressure of component 1:

p1=x1p10p_1 = x_1 \cdot p_1^0
  • Partial pressure of component 2:

p2=x2p20p_2 = x_2 \cdot p_2^0

Where:

  • p1,p2p_1, p_2 = partial vapour pressures

  • x1,x2x_1, x_2 = mole fractions in the liquid phase

  • p10,p20p_1^0, p_2^0 = vapour pressures of pure components


🧪 Total Vapour Pressure (Using Dalton’s Law):

ptotal=p1+p2=x1p10+x2p20p_{\text{total}} = p_1 + p_2 = x_1 p_1^0 + x_2 p_2^0

Also, since x1+x2=1x_1 + x_2 = 1, we can write:

ptotal=p10+(p20p10)x2p_{\text{total}} = p_1^0 + (p_2^0 - p_1^0) \cdot x_2

📈 Graphical Representation:

  • Plot of partial vapour pressure vs mole fraction is a straight line.

  • Plot of total vapour pressure vs mole fraction is also linear for ideal solutions.

📌 For ideal solutions: no volume change, no heat change, and intermolecular forces between components are similar.


📝 Important Points for Exams:

  • Raoult’s Law applies only to ideal solutions (obey the law at all compositions).

  • Used to calculate vapour pressures, boiling points, and composition of vapour phase.

  • More volatile component has a higher pure vapour pressure.


🧠 Example:

Let:

  • p10=100p_1^0 = 100 mm Hg (pure A)

  • p20=50p_2^0 = 50 mm Hg (pure B)

  • x1=0.6,x2=0.4x_1 = 0.6, x_2 = 0.4

Then:

p1=0.6100=60 mm Hgp2=0.450=20 mm Hgp_1 = 0.6 \cdot 100 = 60 \text{ mm Hg} \quad p_2 = 0.4 \cdot 50 = 20 \text{ mm Hg} ptotal=60+20=80 mm Hgp_{\text{total}} = 60 + 20 = 80 \text{ mm Hg}

Would you like a visual diagram of Raoult’s Law (Fig 2.3) or a video script explanation for this?

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